BillFranklin
03-07-2005, 09:58 PM
how would i figure out the odds of more than 1 opponent being dealt a certain hand? how would this differ from figuring out the odds of at least 1 opponent having a hand. I'm asking as more of a general question but to help the discussion lets use Pocket Pairs as an example. if i'm dealt a PP the odds of at least 1 other player (10 handed) being dealt a PP is
(1148/1225)* (1147/1224)* (1146/1223) etc...
how would the math change to figure out odds of say 2 opponents having a PP. would the second number change to
1146/1224 ????
thanks in advance.
(1148/1225)* (1147/1224)* (1146/1223) etc...
how would the math change to figure out odds of say 2 opponents having a PP. would the second number change to
1146/1224 ????
thanks in advance.