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JC21
03-02-2005, 03:35 AM
In the case of XY v. XZ (Y>Z), where both have straight possibilities (i.e. AQ v. AJ), XY is a 3:1 favourite.

When XY v. XZ (Y>Z), where X can make a straight with Y but not with Z (i.e. AQ v. A7), XY is only a 5:2 favourite.

My odds may be incorrect, but why is a hand like AQ less of a favourite against A7 than it is against AJ?

slickpoppa
03-02-2005, 03:42 AM
I think you somewhat answered your own question already.

A7, as opposed to AJ, has a better chance of making straights v. AQ because none of its straight cards are taken by the AQ. With AQ v. AJ, AJ has a smaller chance of making a straight because one of the Q's is not in play.

gaming_mouse
03-02-2005, 03:46 AM
When I ran it in pokerstove, A7 had only about .5% more equity than AJ. slickpoppa may have answered the reason for this. also, AJ and AQ are chopping some straights too. this may have something to do with it.

JC21
03-02-2005, 03:50 AM
Ah, that makes sense. What I was thinking before was that AJ>A7, so AJ should be less of a dog against AQ.

Thanks guys.

kirahvi
03-02-2005, 08:17 AM
Poker hands cannot be compared easily.

A classic example:
AA > KK and KK > 56s, but still 56s has more equity against AA than KK has.

LSU POKER PIMP
03-03-2005, 02:34 AM
SO i guess the best hand to go against AA would be 109s of a different suit

kirahvi
03-03-2005, 04:49 PM
Actually the best hand against AA is exactly 56s. T9s loses some of its straight potential against AA when the board is something like KQJTx.