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Easy E
09-12-2002, 04:57 PM
The Peanuts cartoon today has a simple math quiz for y'all.
Here's the puzzle:
Man has a son and a daughter, with the son 3 years older. In one year, the man will be 6x as old as the daughter is now. In ten years, the man will be 14 years older than the combined ages of his children.

What is the man's present age?

BB King's
09-12-2002, 08:25 PM
41

andyfox
09-13-2002, 12:49 AM
S=D+3

M+1=6D; M=6D-1

M+10=S+10+D+10+14
6D-1+10=D+3+10+D+10+14
6D+9=2D+37
6D=2D+28
4D=28
D=7

M=6D-1
M=42-1=41

BruceZ
09-13-2002, 01:45 AM
s=d+3
m+1=6d
m+10=s+10+d+10+14

m+10=2d+37

subtracting 3 times this equation from the middle equation:

m+1=6d
3m+30=6d+111
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-2m-29=-111

m=41