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View Full Version : KK vs AA probabilty in HE


bigfishead
02-24-2005, 11:56 PM
I cant find my notes on this and dont know how to do the math so dont try explaining it. But I want to know the number.

Also...very interestingly...6 of last 7 times I had KK I was against AA in thelast 24 hrs or so...I actually sucked out 1 time...and wont the hand I wasnt against them...so what are the chances of 6 of 7 times...5 in a row?

Thanks in advance

p.s. I know each time is independent of another. But I would think you could come up with something on the odds of it as such above.

ninjaunderwear
02-25-2005, 07:13 AM
PokerStove tells us...

AA and KK with two shared suits...
Hand 1: 82.6366 % { AdAc }
Hand 2: 17.3634 % { KdKc }

AA and KK with one shared suit...
Hand 1: 81.9461 % { AdAc }
Hand 2: 18.0539 % { KhKd }

AA and KK without any shared suits...
Hand 1: 81.2555 % { AdAc }
Hand 2: 18.7445 % { KsKh }

gaming_mouse
02-25-2005, 11:48 AM
The pokerstove calc just gives you the odds of sucking out -- not the chance the situation occurs in the first place.

Try searching for the answer -- I know that I and many other posters have done the calculation of being up against AA when you have KK a number of times. Let me know if you can't find it.

gm

motorholdem
02-25-2005, 03:35 PM
I don't know if this right, but I'll pose it for others to comment on it.

Let's suppose you have AA at a 10hand table. If the odds for pocket KK are 220 to 1, then would the odds be 22 to 1 (at a 10 hand table) that there are pocket KK when you have AA.????

Note, This does not address how "frequently" AA and KK occur together at the same table. maybe it is (22 to 1) x (22 to 1) (once every 484 hands).

Could someone confirm or disconfirm this??

gaming_mouse
02-25-2005, 03:45 PM
[ QUOTE ]
Let's suppose you have AA at a 10hand table. If the odds for pocket KK are 220 to 1, then would the odds be 22 to 1 (at a 10 hand table) that there are pocket KK when you have AA.????

[/ QUOTE ]

Close. This is the first time of inclusion-exclusion, and it provides a reasonable approximation to the exact answer. Also, be careful about odds and probabilities -- they're different. The chance that you meant to calculate (not the odds) is 9/221 -- there are only 9 oppos, not 10.

pzhon
02-26-2005, 09:45 AM
If you want the probability that someone will be dealt AA and someone will be dealt KK, the probability at a full table is 82,801 / 41,807,675 (http://archiveserver.twoplustwo.com/showthreaded.php?Cat=&Board=&Number=849658&page=&v iew=&sb=5&o=&fpart=) = 1/504.9 .