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VinnyTheFish
02-08-2005, 07:44 PM
Big Pat plays two totally seperate pools. Both follow the same rules for picking numbers. You fill in the names. When all 100 boxes are filled, you pick the numers and teams at random.

Big Pat gets exactly the same set of number ... i.e. NFC 2, AFC 5 on both pools.

what are the odds, please?

tworooks28
02-08-2005, 10:04 PM
Pretty confusing how you stated it. Since I don't really understand the context of your question, I'll try to give an if then statement. If there is 100 possible AFC numbers and also 100 possible NFC numbers in each pool, then you have an 100^2 chance of getting that particular combination in that pool. Then for the first and second pool it would be (100^2)^2, which would be 100,000,000 to 1 chance. Now if there is only 100 possible combinations for each pool, such as you can only get 100 different combinations, then it would be the original 100^2, which would be 10,000 to 1. Hope this isn't confusing and answered your question

tylerdurden
02-08-2005, 11:34 PM
1 in 100.

BugsBunny
02-09-2005, 12:04 AM
I agree with 1 in 100

You have a 1/10 chance of getting the same AFC number and a 1/10 chance of getting the same NFC number. 1/10 * 1/10 = 1/100.

SumZero
02-09-2005, 03:25 AM
Assuming you only get one box on each table then the chance is clearly 1 in 100. You only get one box out of 100 on each. You will get some numbers in the first pool. There will be only one box in the second pool that matches this number. Your chance of getting any given box in the second pool is 1 in 100. So your chance of getting this magic matching number is also 1 in 100. Did you win both pools?

VinnyTheFish
02-09-2005, 08:49 AM
It actually was not me. No he did not win.

I had it (100/100) of getting a (any) number combo in the 1st pool. Multiply that by (1/100) of getting the exact number combo in the other pool.

Thanks for the answers.

It just seemed too low.