Rook80
01-29-2005, 09:33 PM
I just finished reading David Sklansky's article on moving in against the blinds and I have a question on how he determined the # of times you would win if your opponent calls.
I used pokerstove to estimate winning chances with the following hands.
In the first case he talks about an opponent that will call with 7s or better, AK, or AQ. There are 32 hands he could have with AK or AQ. If you have 6s your about a 54% to 46% favorite. This means you should win about 17 hands. Against an overpair your a 20% to 80% underdog. Since there are 48 of these hands you can estimate you will win about 9 of them. This gives you a win ratio in this situation of 26 to 54. In the article, David he estimated you will win 23 of the hands not 26. This is actually about T1000 chip differents in the break even EV value.
Can anyone tell me where he got the estimated # of 23?
I used pokerstove to estimate winning chances with the following hands.
In the first case he talks about an opponent that will call with 7s or better, AK, or AQ. There are 32 hands he could have with AK or AQ. If you have 6s your about a 54% to 46% favorite. This means you should win about 17 hands. Against an overpair your a 20% to 80% underdog. Since there are 48 of these hands you can estimate you will win about 9 of them. This gives you a win ratio in this situation of 26 to 54. In the article, David he estimated you will win 23 of the hands not 26. This is actually about T1000 chip differents in the break even EV value.
Can anyone tell me where he got the estimated # of 23?