Odds of a suited flop?

[David04]

What are the odds of a flop having 3 of the same suit?

I've been seeing this constantly the last week or so.

[Lost Wages]

Ignoring the cards that you hold; 4*C(13,3)/C(52,3) = 5.18%

Lost Wages

[David04]

Thanks.

[MickeyHoldem]

How on earth can you ignore the cards in your hand??

The correct answer is:
(4/17 x (c(11,3) + 3*c(13,3)) / c(50,3)) +
(13/17 x (2*c(12,3) + 2*c(13,3)) / c(50,3)) = 5.18%

Clearly this was an ill-fated attempt at humour!!!

[David04]

I don't get it...your answers are the same.


Clearly that was an ill-fated attempt at humor.

[gaming_mouse]

[ QUOTE ]
How on earth can you ignore the cards in your hand??

[/ QUOTE ]

Quite easily. For example, before any cards are dealt, someone might ask, "What are the chances that the flop is going to come all of one suit on this next hand?"

LostWages answers that question.

gm

[mosdef]

there's a much easier way to arrive at this answer.

you turn over a card. what is the prob that the next two are of the same suit?

2nd = 12/51
3rd = 11/50

prob(event)=12/51 x 11/50 = 5.18%

[MickeyHoldem]

Yes... I understand... I was trying to be funny... my formula takes into account the fact that you have two cards, but includes the possiblility that they are suited or unsuited, and of course it arrives at the same answer... I'll try to keep my humour button under more control. If some may have found my post confusing or troublesome... I appoligize.