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View Full Version : Ed Miller 27/7 ????


Timer
01-01-2005, 06:57 PM
If the board reads k-9-5-3 aren't there 10 ways you can have a set with a k-j already out?

I think I can understand how he comes up with the 27 ways you can make two pair. In order to do this he is eliminating the possibility that the opponent has 95 or 93.

But the set calculation I don't understand. I'm obviously overlooking something simple.

Thanks

pudley4
01-01-2005, 10:27 PM
[ QUOTE ]
If the board reads k-9-5-3 aren't there 10 ways you can have a set with a k-j already out?

I think I can understand how he comes up with the 27 ways you can make two pair. In order to do this he is eliminating the possibility that the opponent has 95 or 93.

But the set calculation I don't understand. I'm obviously overlooking something simple.

Thanks

[/ QUOTE ]

In the book, the player who checkraises you on the turn is the same player who bet into you on the flop. The 3 came on the turn. So unless this guy is retarded (we can still use that word here, right?), he doesn't have 33. So that leaves 1 KK, 3 99, and 3 55 for him to have.