My Hand VS a Range of Hands

[IRV]

Hello All,

Situation:
Player A is an ultratight player known to stay (not reraise) in a raised pot with AKx, AQx, AJx, QQ, JJ, 10 10. Let's assume since he didn't reraise he has no AA or KK.

What are my odds with 2 2 against these range of hands and how do I represent this in a formula where x = my hand and a, b, c represent my opponents hands?

Could it be as simple as taking my hand vs each possible opponent hand and getting the average?

Thanks!

[gaming_mouse]

IRV,

You have to enumerate over all the possiblities and then take a weighted average. This is essentially impossible to do by hand. It's solved using a computer, but luckily the program is already written and you can download it for free.

www.pokerstove.com (http://www.pokerstove.com)

Cheers,
gm

[uuDevil]

When I run this range of hands in Poker Calculator (this is similar to Pokerstove), I get 42% equity for 22. In a 100,000 hand Monte Carlo simulation, it wins 42,051, draws 592, and loses 57,357.