BarkingMad
10-28-2004, 06:35 PM
You are playing No limit Hold Em (tournament or ring, doesn't matter).
You are UTG at a full table and move all in. You somehow know you will only be called by an S&M Group1 hand (AA, KK, QQ, JJ, & AKs).
What is the probability that at least 1 of the 9 players yet to act has an S&M group1 hand?
Does the formula provided by Precision1C & uuDevil in the "Probability of getting a decent hand in the next orbit" thread apply here?
1326 possible hole card combo's
AA thru JJ = 6 each * 4 = 24
AKs = 4
1326 - 28 = 1298 ways to not make an S&M Group1 hand.
1298 / 1326 = .9789
Take .9789 to the power of players yet to act (9) & subtract from 1...
1 - .9789 ^ 9 = .1746
Answer - There is a 17.46% chance that you will be called.
Is this right?
TIA
You are UTG at a full table and move all in. You somehow know you will only be called by an S&M Group1 hand (AA, KK, QQ, JJ, & AKs).
What is the probability that at least 1 of the 9 players yet to act has an S&M group1 hand?
Does the formula provided by Precision1C & uuDevil in the "Probability of getting a decent hand in the next orbit" thread apply here?
1326 possible hole card combo's
AA thru JJ = 6 each * 4 = 24
AKs = 4
1326 - 28 = 1298 ways to not make an S&M Group1 hand.
1298 / 1326 = .9789
Take .9789 to the power of players yet to act (9) & subtract from 1...
1 - .9789 ^ 9 = .1746
Answer - There is a 17.46% chance that you will be called.
Is this right?
TIA