% of hands played?

[BK1248]

If you only play 99- AA, AJ-AK suited or not, what % of the total hands are you playing?

[scandal]

pocket pairs are each C(4,2)=4!/(2! * 2!)=4*3/2=6 combinations
AA-99 is 6 pairs, so 6*6=36 total hands

AK,AQ,AJ are each 4*4=16 combinations, making for 3*16=48 hands

(36+48)/C(52,2)=84/1326=0.0633 or about 6.33%

[DyessMan89]

Around 5%. /images/graemlins/confused.gif

My explanation was easier. /images/graemlins/grin.gif

[zerosum]

[ QUOTE ]
My explanation was easier. /images/graemlins/grin.gif

[/ QUOTE ]

I think of your answer as being a fish, and I think of scandal's answer as being good instruction for catching a fish. /images/graemlins/wink.gif

[Crix]

Surely you must also factor in the number of hands you will play by virtue of being in the BB when there are no raises.