kyro
07-22-2004, 12:51 PM
Incredibly Hypothetical Situation here. But, since there are people that swear they would NEVER fold AA preflop, I'm curious if this situation would change anything.
You're in the BB, first hand of the 10 person SNG. UTG goes all-in. UTG+1 goes all in. MP1 goes all in. While you're trying to figure out what the hell just happened, the SB becomes the ninth person at the table to go all-in. You look at your cards...AA.
I tried looking at this from a mathematical standpoint. Let's say you call. AA has about a 30 percent chance of winning, and if AA wins, you win first place. If the tournament goes by a 2,3,5 payout, you'll win 5 buy-ins. IF you lose, you'll win .555 buy-ins. So on average you'll win 1.8889 buyins.
Now, let's say you fold. Even if you're the worst heads up player in the world, we can say you're guaranteed second place, for an average of 3 buy-ins.
I realize it's not a sure thing that only one person will win the first hand. There's a chance it will be a split pot, which I believe will lower your EV.
Even so, will this lower your EV below the 1.8889 average buy-in if you call? I did a sample where there was a .90 chance that 1 person won the first pot, while there was .10 chance two people split it. My numbers WERE arbitrary, but the EV was 2.56 buy-ins.
Am I crazy? I'm good with numbers normally, but am I way off here? Could folding AA possibly be greater EV than calling with it? Flame away. I could use the abuse if I'm wrong.
You're in the BB, first hand of the 10 person SNG. UTG goes all-in. UTG+1 goes all in. MP1 goes all in. While you're trying to figure out what the hell just happened, the SB becomes the ninth person at the table to go all-in. You look at your cards...AA.
I tried looking at this from a mathematical standpoint. Let's say you call. AA has about a 30 percent chance of winning, and if AA wins, you win first place. If the tournament goes by a 2,3,5 payout, you'll win 5 buy-ins. IF you lose, you'll win .555 buy-ins. So on average you'll win 1.8889 buyins.
Now, let's say you fold. Even if you're the worst heads up player in the world, we can say you're guaranteed second place, for an average of 3 buy-ins.
I realize it's not a sure thing that only one person will win the first hand. There's a chance it will be a split pot, which I believe will lower your EV.
Even so, will this lower your EV below the 1.8889 average buy-in if you call? I did a sample where there was a .90 chance that 1 person won the first pot, while there was .10 chance two people split it. My numbers WERE arbitrary, but the EV was 2.56 buy-ins.
Am I crazy? I'm good with numbers normally, but am I way off here? Could folding AA possibly be greater EV than calling with it? Flame away. I could use the abuse if I'm wrong.